Results 1 to 6 of 6
Thread: Physics Questions...
-
11-14-2012, 09:35 PM #1



- Join Date
- Aug 2009
- Posts
- 20,958
- Country

- Card Cash
- 300.30
- Savings
- 0.00 View my Inventory New
View my store BetaPhysics Questions...
All of my CC to whoever can help me with these two

An archaeologist climb a pyramid in Egypt. The pyramid's height is 105.8 m and its width is 216.3 m. What is the magnitude of the displacement of the archaeologist in meters after she has climbed from the bottom of the pyramid to the top?
The archaeologist now climbs the Great Pyramid in Giza, Egypt. The pyramid's height is 136 m and its width is 230. m. What is the direction of the displacement of the archaeologist in degrees above horizontal after she has climbed from the bottom of the pyramid to the top?
Thanks in advance
Please do NOT tape toploaders or use excessive tape--thanks!Andrew Bailey: 164/218 not including 1/1's (75.2%); 177/407 cards including 1/1's(43.3%); 13/39 Auto, 8/34 Mem, 13/191 1/1's+ 1 auto'd ball +1 auto'd 8x10 + 2 bobble heads + 2 checklist cards + 4 unlisted (including 1 1/1) <WANTLIST-Hidden Content > No international shipping ATM.
Hidden Content
-
11-15-2012, 05:00 PM #2



- Join Date
- Mar 2003
- Posts
- 21,795
- Country

- Card Cash
- 4,487.40
- Savings
- 0.00 View my Inventory New
View my store Beta(105.8)^2 + (216.3)^2 then you take that number and take the square root of it. You should get this 240.78 m. I don't know if it rounds to 240.8 m though it looks like it should in your equation.
The second part remember the SOH CAH TOH method. The sin and cos stuff. If I had a calculator that was doing that stuff I'd figure it out for you but you taking the answer above should get you something in degrees (will be positive) for your answer.Trade Bucket: Hidden Content
-
11-15-2012, 05:14 PM #3



- Join Date
- Aug 2009
- Posts
- 20,958
- Country

- Card Cash
- 300.30
- Savings
- 0.00 View my Inventory New
View my store BetaPlease do NOT tape toploaders or use excessive tape--thanks!Andrew Bailey: 164/218 not including 1/1's (75.2%); 177/407 cards including 1/1's(43.3%); 13/39 Auto, 8/34 Mem, 13/191 1/1's+ 1 auto'd ball +1 auto'd 8x10 + 2 bobble heads + 2 checklist cards + 4 unlisted (including 1 1/1) <WANTLIST-Hidden Content > No international shipping ATM.
Hidden Content
-
11-23-2012, 10:19 AM #4
- Join Date
- Aug 2008
- Posts
- 8,724
- Country

- Card Cash
- 350.00
- Savings
- 0.00 View my Inventory New
View my store Betafor the first one, wouldnt this work? need a calc to finish but try and see:
O (theta) = tan-1 (105.8/216.3)
that gives you your angle, then do pythagorean theorm to get your Hypoteneuse and thats your magnitude of displacement
has it been that long since I did physics haha or does this sound correct? try it out see what happensLast edited by andrewconnors9; 11-23-2012 at 10:33 AM.
Collecting Toronto Maple Leafs Forever Rivals Base and Inserts!
Need Base: 54, 65, 74, 75, 82, 86, 99
Inserts: Double Agents - Lorne Chabot, Playoff Matchups - McCool/Richard
-
11-23-2012, 10:35 AM #5
- Join Date
- Aug 2008
- Posts
- 8,724
- Country

- Card Cash
- 350.00
- Savings
- 0.00 View my Inventory New
View my store Betajust because its a pyramid doesnt change anything, as your not using all dimensions of the pyramid, just doesnt make sense to say in the question "the person walked up a paper thin 1-dimensional inclined plane"
Collecting Toronto Maple Leafs Forever Rivals Base and Inserts!
Need Base: 54, 65, 74, 75, 82, 86, 99
Inserts: Double Agents - Lorne Chabot, Playoff Matchups - McCool/Richard
-
11-23-2012, 02:54 PM #6



- Join Date
- Aug 2009
- Posts
- 20,958
- Country

- Card Cash
- 300.30
- Savings
- 0.00 View my Inventory New
View my store BetaTurns out we had to use the area formula for the pyramid, which is 1/2(b)(h). Thanks!
Please do NOT tape toploaders or use excessive tape--thanks!Andrew Bailey: 164/218 not including 1/1's (75.2%); 177/407 cards including 1/1's(43.3%); 13/39 Auto, 8/34 Mem, 13/191 1/1's+ 1 auto'd ball +1 auto'd 8x10 + 2 bobble heads + 2 checklist cards + 4 unlisted (including 1 1/1) <WANTLIST-Hidden Content > No international shipping ATM.
Hidden Content






eBay Pages
I need your jordan pacheco cards!!!
Hi there I need all the cards I can get of the player listed above and below. Eric Young Jr. I'm looking to do an even swap so one card for another type thing. Thanks for taking the time to look.
Yesterday, 04:50 PM in patsgetgronked